5b^2+6b-144=0

Solution for 5b^2+6b-144=0 equation:

5b^2+6b-144=0

a = 5; b = 6; c = -144;
Δ = b2-4ac
Δ = 62-4·5·(-144)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*5}=\frac{-60}{10}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*5}=\frac{48}{10}
=4+4/5
$